\clearpage\newpage
 \section{Math constants and functions} % (fold)
 \label{sec:math_functions}

\bgroup
\catcode`_=12 
\small
\captionof{table}{Math constants and functions.}\label{misc}
\begin{tabular}{ll}
\toprule
\textbf{contants or functions} & \textbf{Comments}\\
\midrule
\Igfct{math}{tkzphi}     &  constant $\varphi  = (1+math.sqrt(5))/2 $\\
\Igfct{math}{tkzinvphi}   &  constant $1/\varphi  = 1/tkzphi$\\
\Igfct{math}{tkzsqrtphi}    &  constant $\sqrt{\varphi}= math.sqrt(tkzphi)$    \\
%round(num, idp)    &  \\
%tkzround( num, idp )   &   \\
% Cramer33(a1,a2,a3,b1,b2,b3,c1,c2,c3) &  \\
% Cramer22(a1,a2,b1,b2)  &   \\
\Igfct{math}{length (a,b) }     &  point.abs(a-b) [\ref{sub:report_de_distance}]  \\
\Igfct{math}{islinear (z1,z2,z3) }   & Are the points aligned? (z2-z1) $\parallel$ (z3-z1) ?  \\
\Igfct{math}{isortho (z1,z2,z3)} &  (z2-z1) $\perp$ (z3-z1)  ? boolean\\
\Igfct{math}{get\_angle (z1,z2,z3)} & the vertex is z1 [\ref{sub:get_angle}] \\
\Igfct{math}{bisector (z1,z2,z3)} & L.Aa = bisector (z.A,z.B,z.C) from A [\ref{sub:get_angle}] \\
\Igfct{math}{bisector\_ext (z1,z2,z3)} & L.Aa = bisector_ext (z.A,z.B,z.C) from A \\
\Igfct{math}{altitude (z1,z2,z3)} & altitude from z1 \\
\Igfct{package}{set\_lua\_to\_tex (list)}   & set\_lua\_to\_tex('a','n') defines |\a| and |\n|   \\
%parabola (a,b,c)   & to get   \\
\Igfct{math}{value (v) }     &  apply |scale * value |    \\
\Igfct{math}{real (v) }     &  apply  | value /scale |     \\
\Igfct{math}{angle\_normalize (an) }   &  to get a value between 0 and $2\pi$ \\
\Igfct{misc}{barycenter (\{z1,n1\},\{z2,n2\}, ...)} & barycenter of list of points  \\
\Igfct{math}{solve\_quadratic (a,b,c) }   & gives the solution of $ax^2+bx+c =0$  a,b,c real or complex  [\ref{ssub:function_solve__quadratic}] \\
\bottomrule
\end{tabular}
\egroup

\subsection{Length of a segment} % (fold)
\label{sub:length_of_a_segment}
|length(z.A,z.B)| is a shortcut for |point.abs(z.A-z.B)|. This avoids the need to use complexes.

% subsection length_of_a_segment (end)


\subsection{Harmonic division with tkzphi } % (fold)
\label{sub:harmonic_division_with_tkzphi}
\begin{Verbatim}
\directlua{%
init_elements ()
   scale =.5
   z.a = point: new(0,0)
   z.b = point: new(8,0)
   L.ab = line: new (z.a,z.b)
   z.m,z.n = L.ab: harmonic_both (tkzphi)
}
\begin{tikzpicture}
   \tkzGetNodes
   \tkzDrawLine[add= .2 and .2](a,n) 
   \tkzDrawPoints(a,b,n,m)
   \tkzLabelPoints(a,b,n,m)
\end{tikzpicture}
\end{Verbatim}


\directlua{%
init_elements ()
   scale =.25
   z.a = point: new(0,0)
   z.b = point: new(8,0)
   L.ab = line: new (z.a,z.b)
   z.m,z.n = L.ab: harmonic_both (tkzphi)
}
\hspace*{\fill}
\begin{tikzpicture}
   \tkzGetNodes
   \tkzDrawLine[add= .1 and .1](a,n) 
   \tkzDrawPoints(a,b,n,m)
   \tkzLabelPoints(a,b,n,m)
\end{tikzpicture}
 \hspace*{\fill}
% subsection harmonic_division_with_tkzphi (end)

\subsection{Function islinear} % (fold)
\label{sub:function_islinear}
\begin{minipage}{0.5\textwidth}
\begin{Verbatim}
\directlua{%
init_elements ()
   z.a = point: new (1, 1)
   z.b = point: new (2, 2)
   z.c = point: new (4, 4)
   if islinear (z.a,z.b,z.c) then
       z.d = point: new (0, 0)
    else 
        z.d = point: new (-1, -1)
   end
}
\begin{tikzpicture}
    \tkzGetNodes
    \tkzDrawPoints(a,...,d)
    \tkzLabelPoints(a,...,d)
\end{tikzpicture}
\end{Verbatim}
\end{minipage}
\begin{minipage}{0.5\textwidth}
\directlua{%
init_elements ()
   z.a = point: new (1, 1)
   z.b = point: new (2, 2)
   z.c = point: new (4, 4)
   if islinear (z.a,z.b,z.c) then
       z.d = point: new (0, 0)
    else 
        z.d = point: new (-1, -1)
   end
}
 \hspace*{\fill}
\begin{tikzpicture}
    \tkzGetNodes
    \tkzDrawPoints(a,...,d)
    \tkzLabelPoints(a,...,d)
\end{tikzpicture}
\hspace*{\fill}
\end{minipage}

% subsection function_islinear (end)

\subsection{Function  value }% (fold)
\label{sub:function_value}

value to apply scaling if necessary

If |scale = 1.2| with a = value(5) the actual value of |a| will be $5\times 1.2 = 6$.

% subsubsection function_value (end)

\subsection{Function  real }% (fold)
\label{ssub:function_real}

If |scale = 1.2| with a = 6 then real(a) = $6 / 1.2 = 5$ .

% subsection function_real (end)


\subsection{Transfer from lua to \TEX} % (fold)
\label{sub:transfer_from_lua_to_tex}
It's possible to transfer variable from Lua to \TEX{} with the macro 
\tkzcname{tkzUseLua}.


\begin{minipage}{.5\textwidth}
\begin{Verbatim}
\directlua{%
init_elements ()
   z.A            = point : new (0 , 0)
   z.B            = point : new (3 , 2)
   z.C            = point : new (2 , 5)
   L.AB           = line : new (z.A,z.B)
   d              = L.AB : distance (z.C)
   l              = L.AB.length
   z.H            = L.AB : projection (z.C)
}
\begin{tikzpicture}
\tkzGetNodes
\tkzDrawLines(A,B C,H)
\tkzDrawPoints(A,B,C,H)
\tkzLabelPoints(A,B,C,H)
\tkzLabelSegment[above right,draw](C,H){$CH = \tkzUseLua{d}$}
\tkzLabelSegment[below right,draw](A,B){$AB = \tkzUseLua{l}$}
\end{tikzpicture}
\end{Verbatim}
\end{minipage}
\begin{minipage}{.5\textwidth}
\directlua{%
init_elements ()
   z.A            = point : new (0 , 0)
   z.B            = point : new (3 , 2)
   z.C            = point : new (2 , 5)
   L.AB           = line : new (z.A,z.B)
   d              = L.AB : distance (z.C)
   l              = L.AB.length
   z.H            = L.AB : projection (z.C)
}
 \hspace*{\fill}
\begin{tikzpicture}
\tkzGetNodes
\tkzDrawLines(A,B C,H)
\tkzDrawPoints(A,B,C,H)
\tkzLabelPoints(A,B,C,H)
\tkzLabelSegment[above right,draw](C,H){$CH = \tkzUseLua{d}$}
\tkzLabelSegment[below right,draw](A,B){$AB = \tkzUseLua{l}$}
\end{tikzpicture}
\end{minipage}
% subsection transfer_from_lua_to_tex (end)

\subsection{Normalized angles : Slope of lines (ab), (ac) and (ad)} % (fold)
\label{sub:normalized_angles}
\begin{Verbatim}
\directlua{%
init_elements ()
   z.a      = point: new(0, 0)
   z.b      = point: new(-3, -3)
   z.c      = point: new(0, 3)
   z.d      = point: new(2, -2)
   angle    = point.arg (z.b-z.a)
   tex.print('slope of (ab) : '..tostring(angle)..'\\\\')
   tex.print('slope normalized of (ab) : '..tostring(angle\_normalize(angle))..'\\\\')
   angle    = point.arg (z.c-z.a)
   tex.print('slope of (ac) : '..tostring(angle)..'\\\\')
   tex.print('slope normalized of (ac) : '..tostring(angle\_normalize(angle))..'\\\\')
   angle    = point.arg (z.d-z.a)
   tex.print('slope of (ad) : '..tostring(angle)..'\\\\')
   tex.print('slope normalized of (acd) : '..tostring(angle\_normalize(angle))..'\\\\')
}
\begin{tikzpicture}
   \tkzGetNodes
   \tkzDrawLines[red](a,b a,c a,d)
   \tkzDrawPoints(a,b,c,d)
   \tkzLabelPoints(a,b,c,d)
\end{tikzpicture}
\end{Verbatim}
\directlua{%
init_elements ()
  scale = .75
z.a = point: new(0, 0)
z.b = point: new(-3, -3)
z.c = point: new(0, 3)
z.d = point: new(2, -2)
angle = point.arg (z.b-z.a)
tex.print('slope of (ab) : '..tostring(angle)..'\\\\')
tex.print('slope normalized of (ab) : '..tostring(angle_normalize(angle))..'\\\\')
angle = point.arg (z.c-z.a)
tex.print('slope of (ac) : '..tostring(angle)..'\\\\')
tex.print('slope normalized of (ac) : '..tostring(angle_normalize(angle))..'\\\\')
angle = point.arg (z.d-z.a)
tex.print('slope of (ad) : '..tostring(angle)..'\\\\')
tex.print('slope normalized of (ad) : '..tostring(angle_normalize(angle))..'\\\\')
}

  \hspace*{\fill}
\begin{tikzpicture}
   \tkzGetNodes
   \tkzDrawLines[red](a,b a,c a,d)
   \tkzDrawPoints(a,b,c,d)
   \tkzLabelPoints(a,b,c,d)
\end{tikzpicture}
 \hspace*{\fill}

% subsection normalized_angles (end)

\subsection{Get angle} % (fold)
\label{sub:get_angle}

The function  |get_angle (a,b,c)| gives the angle normalized of $(\overrightarrow{ab},\overrightarrow{ac})$.

\begin{minipage}{0.6\textwidth}
\begin{Verbatim}
\directlua{%
init_elements ()
   z.a   = point: new(0, 0)
   z.b   = point: new(-2, -2)
   z.c   = point: new(0, 3)
   angcb = tkzround ( get_angle (z.a,z.c,z.b),3)
   angbc = tkzround ( get_angle (z.a,z.b,z.c),3)
}

\begin{tikzpicture}
   \tkzGetNodes
   \tkzDrawLines[red](a,b a,c)
   \tkzDrawPoints(a,b,c)
   \tkzLabelPoints(a,b,c)
   \tkzMarkAngle[->](c,a,b)
   \tkzLabelAngle(c,a,b){\tkzUseLua{angcb}}
   \tkzMarkAngle[->](b,a,c)
   \tkzLabelAngle(b,a,c){\tkzUseLua{angbc}}
\end{tikzpicture}
\end{Verbatim}
\end{minipage}
\begin{minipage}{0.4\textwidth}
\directlua{%
init_elements ()
   scale = 1.2
   z.a   = point: new(0, 0)
   z.b   = point: new(-2, -2)
   z.c   = point: new(0, 3)
   angcb = tkzround ( get_angle (z.a,z.c,z.b),3)
   angbc = tkzround ( get_angle (z.a,z.b,z.c),3)
}

\hspace*{\fill}
\begin{tikzpicture}
\tkzGetNodes
\tkzDrawLines[red](a,b a,c)
\tkzDrawPoints(a,b,c)
\tkzLabelPoints(a,b,c)
\tkzMarkAngle[->](c,a,b)
\tkzLabelAngle(c,a,b){\tkzUseLua{angcb}}
\tkzMarkAngle[->](b,a,c)
\tkzLabelAngle(b,a,c){\tkzUseLua{angbc}}
\end{tikzpicture}
\hspace*{\fill}
\end{minipage}
% subsection get_angle (end)

\subsection{Dot or scalar product} % (fold)
\label{sub:dot_or_scalar_product}

\begin{minipage}{0.5\textwidth}
\begin{Verbatim}
\directlua{%
init_elements ()
   z.A    = point: new(0,0)
   z.B    = point: new(5,0)
   z.C    = point: new(0,3)
   T.ABC  = triangle: new (z.A,z.B,z.C)
   z.A_1,
   z.B_1,
   z.C_1  = get_points (T.ABC: anti ())
   x  = dot_product (z.A,z.B,z.C)
}
\begin{tikzpicture}
   \tkzGetNodes
   \tkzDrawPolygon(A,B,C)
   \tkzDrawPoints(A,B,C,A_1,B_1,C_1)
   \tkzLabelPoints(A,B,C,A_1,B_1,C_1)
   \tkzDrawPolygon[blue](A_1,B_1,C_1)
   \tkzText[right](0,-1){dot product =\tkzUseLua{x}}
\end{tikzpicture}
\end{Verbatim}
\end{minipage}
\begin{minipage}{0.5\textwidth}
\directlua{%
init_elements ()
 scale  = .6
 z.A    = point: new(0,0)
 z.B    = point: new(5,0)
 z.C    = point: new(0,3)
 T.ABC  = triangle: new (z.A,z.B,z.C)
 z.A_1,
 z.B_1,
 z.C_1  = get_points (T.ABC: anti ())
 x  = dot_product (z.A,z.B,z.C)
}
\hspace*{\fill}
\begin{tikzpicture}
   \tkzGetNodes
   \tkzDrawPolygon(A,B,C)
   \tkzDrawPoints(A,B,C,A_1,B_1,C_1)
   \tkzLabelPoints(A,B,C,A_1,B_1,C_1)
   \tkzDrawPolygon[blue](A_1,B_1,C_1)
   \tkzText[right](0,-1){dot product =\tkzUseLua{x}}
   \end{tikzpicture}
\hspace*{\fill}
\end{minipage}

The scalar product of the vectors $\overrightarrow{AC}$ and $\overrightarrow{AB}$ is equal to $\tkzUseLua{x}$, so these vectors are orthogonal.
% subsection dot_or_scalar_product (end)

\subsection{Alignment or orthogonality} % (fold)
\label{sub:alignment_or_orthogonality}

With the functions |islinear| and |isortho|. |islinear(z.a,z.b,z.c)| gives |true| idf the points $a$, $b$ and $c$ are aligned.

|isortho(z.a,z.b,z.c)| gives |true| if the line $(ab)$ is orthogonal to the line $(ac)$.
% subsection alignment_or_orthogonality (end)

\subsection{Bisector and altitude} % (fold)
\label{sub:bisector_and_altitude}
These functions are useful if you don't need to create a useful triangle object for the rest of your code.

\begin{minipage}{.5\textwidth}
   \begin{Verbatim}
\directlua{%
init_elements ()
   z.a   = point: new (0, 0)
   z.b   = point: new (5, -2)
   z.c   = point: new (2, 3)
   z.i   = bisector (z.a,z.c,z.b).pb
   z.h   = altitude (z.b,z.a,z.c).pb
   angic = tkzround ( get_angle (z.a,z.i,z.c),2)
   angci = tkzround ( get_angle (z.a,z.b,z.i),2)
   z.e = bisector_ext (z.a,z.b,z.c).pb
}

\begin{tikzpicture}
   \tkzGetNodes
   \tkzDrawPolygon(a,b,c)
   \tkzDrawSegments(a,i b,h a,e)
   \tkzDrawPoints(a,b,c,i,h)
   \tkzLabelPoints(a,b)
   \tkzLabelPoints[above](c,i,h)
   \tkzMarkAngle[->](i,a,c)
   \tkzLabelAngle[font=\tiny,pos=.75](i,a,c){\tkzUseLua{angci}}
   \tkzMarkAngle[<-](b,a,i)
   \tkzLabelAngle[font=\tiny,pos=.75](b,a,i){\tkzUseLua{angic}}
\end{tikzpicture}
   \end{Verbatim}
\end{minipage}
\begin{minipage}{.5\textwidth}
\directlua{%
init_elements ()
   z.a   = point: new (0, 0)
   z.b   = point: new (5, -2)
   z.c   = point: new (2, 3)
   z.i   = bisector (z.a,z.c,z.b).pb
   z.h   = altitude (z.b,z.a,z.c).pb
   angic = tkzround ( get_angle (z.a,z.i,z.c),2)
   angci = tkzround ( get_angle (z.a,z.b,z.i),2)
   z.e = bisector_ext (z.a,z.b,z.c).pb
}
\hspace{\fill}
\begin{tikzpicture}
   \tkzGetNodes
   \tkzDrawPolygon(a,b,c)
   \tkzDrawSegments(a,i b,h a,e)
   \tkzDrawPoints(a,b,c,i,h)
   \tkzLabelPoints(a,b)
   \tkzLabelPoints[above](c,i,h)
   \tkzMarkAngle[->](i,a,c)
   \tkzLabelAngle[font=\tiny,pos=.75](i,a,c){\tkzUseLua{angci}}
   \tkzMarkAngle[<-](b,a,i)
   \tkzLabelAngle[font=\tiny,pos=.75](b,a,i){\tkzUseLua{angic}}
\end{tikzpicture}
\end{minipage}
% subsection bisector_and_altitude (end)

\subsection{Other functions} % (fold)
\label{sub:other_functions}

Not documented because still in beta version: |parabola|, |Cramer22|, |Cramer33|.

% subsection other_functions (end)

\subsubsection{Function solve\_quadratic} % (fold)
\label{ssub:function_solve__quadratic}

This function solves the equation $ax^2+bx+c= 0$ with real or complex numbers.

\begin{minipage}{.6\textwidth}
\begin{Verbatim}
\directlua{%
init_elements ()
    tex.sprint('Solve : $x^2+1=0$ The solution set is  ')
    r1,r2 = solve_quadratic(1,0,1)
    tex.print('\\{'..tostring(r1)..' , '..tostring(r2)..'\\}')
    tex.print('\\\\')
    tex.sprint('Solve : $x^2+2x-3=0$ The solution set is  ')
    r1,r2 = solve_quadratic(1,2,-3)
    tex.print('\\{'..tostring(r1)..' , '..tostring(r2)..'\\}')
    tex.print('\\\\')
    a = point (0,1)
    b = point (1,1)
    c = point (-1,1)
    tex.sprint('Solve : $ix^2+(1+i)x+(-1+i)=0$ The solution set is  ')
    r1,r2 = solve_quadratic(a,b,c)
    tex.print('\\{'..tostring(r1)..' , '..tostring(r2)..'\\}')
}
\end{Verbatim}
\end{minipage}

\directlua{%
init_elements ()
    tex.sprint('Solve : $x^2+1=0$ The solution set is  ')
    r1,r2 = solve_quadratic(1,0,1)
    tex.print('\\{'..tostring(r1)..' , '..tostring(r2)..'\\}')
    tex.print('\\\\')
    tex.sprint('Solve : $x^2+2x-3=0$ The solution set is  ')
    r1,r2 = solve_quadratic(1,2,-3)
    tex.print('\\{'..tostring(r1)..' , '..tostring(r2)..'\\}')
    tex.print('\\\\')
    a = point (0,1)
    b = point (1,1)
    c = point (-1,1)
    tex.sprint('Solve : $ix^2+(1+i)x+(-1+i)=0$ The solution set is  ')
    r1,r2 = solve_quadratic(a,b,c)
    tex.print('\\{'..tostring(r1)..' , '..tostring(r2)..'\\}')
}

% subsubsection function_solve__quadratic (end)
% section math_functions (end)

\endinput